The emphasis for this week in my non-linear physics class was on phase
space. Analysis of dynamical systems in phase space (or
configuration/state space) converts a numerical problem into a
geometric one. Even if you aren’t able to solve the underlying
differential equation, the geometric picture helps you make
predictions on the behavior of the system. From control engineering,
an analogy with the Root Locus method was drawn.

The picture above shows the phase space for the pendulum equation:

Each point on the phase space acts as an initial condition for the
system. As I had written earlier, solving this equation is not
trivial. If instead we look at the phase plane, we can determine three
distinct regions of operations:
- fixed points at the origin and at the intersection of the two red
lines. These correspond to steady states, but aren’t very
interesting.
- closed orbits around the origin. These correspond to periodic
motions.
- trajectories apart from orbits and fixed points.
Physically, we can reason that for a high initial velocity (higher up
on y-axis), the period tends to infinity. The position (x-axis) also
increases constantly.
First Integral


![[ \frac{1}{2} (\theta^\prime)^2]^\prime + [ -\cos \theta]^\prime = 0 [ \frac{1}{2} (\theta^\prime)^2]^\prime + [ -\cos \theta]^\prime = 0](http://ergodicity.iamganesh.com/wp-content/latexrenderer/pictures/18e0e1eed191566af17429e55da066f6.gif)
![[ \frac{1}{2} (\theta^\prime)^2 -\cos \theta]^\prime = 0 [ \frac{1}{2} (\theta^\prime)^2 -\cos \theta]^\prime = 0](http://ergodicity.iamganesh.com/wp-content/latexrenderer/pictures/762aaaa997110bedf583625586dc2d6b.gif)
which means that

where
is a constant. These indicate level curves
in the phase plane, corresponding to constant “energy.”
For non-dissipative systems, flows in phase space have constant
volume. If you were to pick a circle centered around one of the
periodic trajectories, representing an ensemble of trajectories, then
the area (in 2D) of the circle remains constant. Ofcourse, if the
trajectories are not circle (as they are near the origin), the circle
we initially start with gets deformed. This can be seen in the
following figure:

Computing the area of the circle is simple, but computing the area of
the arbitrary deformed polygon is a little harder. This is the focus of
the next section.
Area of a polygon
Consider a polygon of N edges with vertices (x_i,y_i). The polygon
should also be closed so that (x_0,y_0) is the same vertex as
(x_N,y_N). The area is given by

This method works by projecting a line from each vertex to a
horizontal line (usually the x-axis) below polygon. The area enclosed
between two such line segments is the sum of the area of the triangle
in the polygon and the area of the trapezoid outside the polygon. As
we loop through the vertices of the polygon, the area outside the
polygon eventually cancels out. This is a form of the Stokes Theorem.